Optimal. Leaf size=434 \[ \frac{i e^{i a} f (c+d x)^2 (d e-c f)^2 \text{Gamma}\left (\frac{2}{3},-i b (c+d x)^3\right )}{2 d^4 \left (-i b (c+d x)^3\right )^{2/3}}-\frac{i e^{-i a} f (c+d x)^2 (d e-c f)^2 \text{Gamma}\left (\frac{2}{3},i b (c+d x)^3\right )}{2 d^4 \left (i b (c+d x)^3\right )^{2/3}}+\frac{i e^{i a} (c+d x) (d e-c f)^3 \text{Gamma}\left (\frac{1}{3},-i b (c+d x)^3\right )}{6 d^4 \sqrt [3]{-i b (c+d x)^3}}-\frac{i e^{-i a} (c+d x) (d e-c f)^3 \text{Gamma}\left (\frac{1}{3},i b (c+d x)^3\right )}{6 d^4 \sqrt [3]{i b (c+d x)^3}}-\frac{e^{i a} f^3 (c+d x) \text{Gamma}\left (\frac{1}{3},-i b (c+d x)^3\right )}{18 b d^4 \sqrt [3]{-i b (c+d x)^3}}-\frac{e^{-i a} f^3 (c+d x) \text{Gamma}\left (\frac{1}{3},i b (c+d x)^3\right )}{18 b d^4 \sqrt [3]{i b (c+d x)^3}}-\frac{f^2 (d e-c f) \cos \left (a+b (c+d x)^3\right )}{b d^4}-\frac{f^3 (c+d x) \cos \left (a+b (c+d x)^3\right )}{3 b d^4} \]
[Out]
________________________________________________________________________________________
Rubi [A] time = 0.444276, antiderivative size = 434, normalized size of antiderivative = 1., number of steps used = 14, number of rules used = 9, integrand size = 20, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.45, Rules used = {3433, 3355, 2208, 3389, 2218, 3379, 2638, 3385, 3356} \[ \frac{i e^{i a} f (c+d x)^2 (d e-c f)^2 \text{Gamma}\left (\frac{2}{3},-i b (c+d x)^3\right )}{2 d^4 \left (-i b (c+d x)^3\right )^{2/3}}-\frac{i e^{-i a} f (c+d x)^2 (d e-c f)^2 \text{Gamma}\left (\frac{2}{3},i b (c+d x)^3\right )}{2 d^4 \left (i b (c+d x)^3\right )^{2/3}}+\frac{i e^{i a} (c+d x) (d e-c f)^3 \text{Gamma}\left (\frac{1}{3},-i b (c+d x)^3\right )}{6 d^4 \sqrt [3]{-i b (c+d x)^3}}-\frac{i e^{-i a} (c+d x) (d e-c f)^3 \text{Gamma}\left (\frac{1}{3},i b (c+d x)^3\right )}{6 d^4 \sqrt [3]{i b (c+d x)^3}}-\frac{e^{i a} f^3 (c+d x) \text{Gamma}\left (\frac{1}{3},-i b (c+d x)^3\right )}{18 b d^4 \sqrt [3]{-i b (c+d x)^3}}-\frac{e^{-i a} f^3 (c+d x) \text{Gamma}\left (\frac{1}{3},i b (c+d x)^3\right )}{18 b d^4 \sqrt [3]{i b (c+d x)^3}}-\frac{f^2 (d e-c f) \cos \left (a+b (c+d x)^3\right )}{b d^4}-\frac{f^3 (c+d x) \cos \left (a+b (c+d x)^3\right )}{3 b d^4} \]
Antiderivative was successfully verified.
[In]
[Out]
Rule 3433
Rule 3355
Rule 2208
Rule 3389
Rule 2218
Rule 3379
Rule 2638
Rule 3385
Rule 3356
Rubi steps
\begin{align*} \int (e+f x)^3 \sin \left (a+b (c+d x)^3\right ) \, dx &=\frac{\operatorname{Subst}\left (\int \left (d^3 e^3 \left (1-\frac{c f \left (3 d^2 e^2-3 c d e f+c^2 f^2\right )}{d^3 e^3}\right ) \sin \left (a+b x^3\right )+3 d^2 e^2 f \left (1+\frac{c f (-2 d e+c f)}{d^2 e^2}\right ) x \sin \left (a+b x^3\right )+3 d e f^2 \left (1-\frac{c f}{d e}\right ) x^2 \sin \left (a+b x^3\right )+f^3 x^3 \sin \left (a+b x^3\right )\right ) \, dx,x,c+d x\right )}{d^4}\\ &=\frac{f^3 \operatorname{Subst}\left (\int x^3 \sin \left (a+b x^3\right ) \, dx,x,c+d x\right )}{d^4}+\frac{\left (3 f^2 (d e-c f)\right ) \operatorname{Subst}\left (\int x^2 \sin \left (a+b x^3\right ) \, dx,x,c+d x\right )}{d^4}+\frac{\left (3 f (d e-c f)^2\right ) \operatorname{Subst}\left (\int x \sin \left (a+b x^3\right ) \, dx,x,c+d x\right )}{d^4}+\frac{(d e-c f)^3 \operatorname{Subst}\left (\int \sin \left (a+b x^3\right ) \, dx,x,c+d x\right )}{d^4}\\ &=-\frac{f^3 (c+d x) \cos \left (a+b (c+d x)^3\right )}{3 b d^4}+\frac{f^3 \operatorname{Subst}\left (\int \cos \left (a+b x^3\right ) \, dx,x,c+d x\right )}{3 b d^4}+\frac{\left (f^2 (d e-c f)\right ) \operatorname{Subst}\left (\int \sin (a+b x) \, dx,x,(c+d x)^3\right )}{d^4}+\frac{\left (3 i f (d e-c f)^2\right ) \operatorname{Subst}\left (\int e^{-i a-i b x^3} x \, dx,x,c+d x\right )}{2 d^4}-\frac{\left (3 i f (d e-c f)^2\right ) \operatorname{Subst}\left (\int e^{i a+i b x^3} x \, dx,x,c+d x\right )}{2 d^4}+\frac{\left (i (d e-c f)^3\right ) \operatorname{Subst}\left (\int e^{-i a-i b x^3} \, dx,x,c+d x\right )}{2 d^4}-\frac{\left (i (d e-c f)^3\right ) \operatorname{Subst}\left (\int e^{i a+i b x^3} \, dx,x,c+d x\right )}{2 d^4}\\ &=-\frac{f^2 (d e-c f) \cos \left (a+b (c+d x)^3\right )}{b d^4}-\frac{f^3 (c+d x) \cos \left (a+b (c+d x)^3\right )}{3 b d^4}+\frac{i e^{i a} (d e-c f)^3 (c+d x) \Gamma \left (\frac{1}{3},-i b (c+d x)^3\right )}{6 d^4 \sqrt [3]{-i b (c+d x)^3}}-\frac{i e^{-i a} (d e-c f)^3 (c+d x) \Gamma \left (\frac{1}{3},i b (c+d x)^3\right )}{6 d^4 \sqrt [3]{i b (c+d x)^3}}+\frac{i e^{i a} f (d e-c f)^2 (c+d x)^2 \Gamma \left (\frac{2}{3},-i b (c+d x)^3\right )}{2 d^4 \left (-i b (c+d x)^3\right )^{2/3}}-\frac{i e^{-i a} f (d e-c f)^2 (c+d x)^2 \Gamma \left (\frac{2}{3},i b (c+d x)^3\right )}{2 d^4 \left (i b (c+d x)^3\right )^{2/3}}+\frac{f^3 \operatorname{Subst}\left (\int e^{-i a-i b x^3} \, dx,x,c+d x\right )}{6 b d^4}+\frac{f^3 \operatorname{Subst}\left (\int e^{i a+i b x^3} \, dx,x,c+d x\right )}{6 b d^4}\\ &=-\frac{f^2 (d e-c f) \cos \left (a+b (c+d x)^3\right )}{b d^4}-\frac{f^3 (c+d x) \cos \left (a+b (c+d x)^3\right )}{3 b d^4}-\frac{e^{i a} f^3 (c+d x) \Gamma \left (\frac{1}{3},-i b (c+d x)^3\right )}{18 b d^4 \sqrt [3]{-i b (c+d x)^3}}+\frac{i e^{i a} (d e-c f)^3 (c+d x) \Gamma \left (\frac{1}{3},-i b (c+d x)^3\right )}{6 d^4 \sqrt [3]{-i b (c+d x)^3}}-\frac{e^{-i a} f^3 (c+d x) \Gamma \left (\frac{1}{3},i b (c+d x)^3\right )}{18 b d^4 \sqrt [3]{i b (c+d x)^3}}-\frac{i e^{-i a} (d e-c f)^3 (c+d x) \Gamma \left (\frac{1}{3},i b (c+d x)^3\right )}{6 d^4 \sqrt [3]{i b (c+d x)^3}}+\frac{i e^{i a} f (d e-c f)^2 (c+d x)^2 \Gamma \left (\frac{2}{3},-i b (c+d x)^3\right )}{2 d^4 \left (-i b (c+d x)^3\right )^{2/3}}-\frac{i e^{-i a} f (d e-c f)^2 (c+d x)^2 \Gamma \left (\frac{2}{3},i b (c+d x)^3\right )}{2 d^4 \left (i b (c+d x)^3\right )^{2/3}}\\ \end{align*}
Mathematica [F] time = 102.679, size = 0, normalized size = 0. \[ \int (e+f x)^3 \sin \left (a+b (c+d x)^3\right ) \, dx \]
Verification is Not applicable to the result.
[In]
[Out]
________________________________________________________________________________________
Maple [F] time = 0.157, size = 0, normalized size = 0. \begin{align*} \int \left ( fx+e \right ) ^{3}\sin \left ( a+ \left ( dx+c \right ) ^{3}b \right ) \, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (f x + e\right )}^{3} \sin \left ({\left (d x + c\right )}^{3} b + a\right )\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Fricas [A] time = 1.97094, size = 1007, normalized size = 2.32 \begin{align*} -\frac{{\left (3 \, b d^{3} e^{3} - 9 \, b c d^{2} e^{2} f + 9 \, b c^{2} d e f^{2} - 3 \, b c^{3} f^{3} - i \, f^{3}\right )} \left (i \, b d^{3}\right )^{\frac{2}{3}} e^{\left (-i \, a\right )} \Gamma \left (\frac{1}{3}, i \, b d^{3} x^{3} + 3 i \, b c d^{2} x^{2} + 3 i \, b c^{2} d x + i \, b c^{3}\right ) +{\left (3 \, b d^{3} e^{3} - 9 \, b c d^{2} e^{2} f + 9 \, b c^{2} d e f^{2} - 3 \, b c^{3} f^{3} + i \, f^{3}\right )} \left (-i \, b d^{3}\right )^{\frac{2}{3}} e^{\left (i \, a\right )} \Gamma \left (\frac{1}{3}, -i \, b d^{3} x^{3} - 3 i \, b c d^{2} x^{2} - 3 i \, b c^{2} d x - i \, b c^{3}\right ) + 9 \,{\left (b d^{3} e^{2} f - 2 \, b c d^{2} e f^{2} + b c^{2} d f^{3}\right )} \left (i \, b d^{3}\right )^{\frac{1}{3}} e^{\left (-i \, a\right )} \Gamma \left (\frac{2}{3}, i \, b d^{3} x^{3} + 3 i \, b c d^{2} x^{2} + 3 i \, b c^{2} d x + i \, b c^{3}\right ) + 9 \,{\left (b d^{3} e^{2} f - 2 \, b c d^{2} e f^{2} + b c^{2} d f^{3}\right )} \left (-i \, b d^{3}\right )^{\frac{1}{3}} e^{\left (i \, a\right )} \Gamma \left (\frac{2}{3}, -i \, b d^{3} x^{3} - 3 i \, b c d^{2} x^{2} - 3 i \, b c^{2} d x - i \, b c^{3}\right ) + 6 \,{\left (b d^{3} f^{3} x + 3 \, b d^{3} e f^{2} - 2 \, b c d^{2} f^{3}\right )} \cos \left (b d^{3} x^{3} + 3 \, b c d^{2} x^{2} + 3 \, b c^{2} d x + b c^{3} + a\right )}{18 \, b^{2} d^{6}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \left (e + f x\right )^{3} \sin{\left (a + b c^{3} + 3 b c^{2} d x + 3 b c d^{2} x^{2} + b d^{3} x^{3} \right )}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (f x + e\right )}^{3} \sin \left ({\left (d x + c\right )}^{3} b + a\right )\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]